I"m do the efforts to construct a basic histogram through ggplot2 package in R.I"m loading my data from a csv file and putting 2 of the columns with each other in a data frame, choose this:

df = data.frame(sp = data$species, cov = data$totalcover)sp is recognised together a variable of 23 level (my variety of lines) and cov as 23 numbers.Then, to construct the histogram, I"m executing this:

ggplot(df, aes(df$sp, df$cov) + geom_histogram())However, R returns the error: "Error: Mapping should be produced with aes() or aes_()."

How is this feasible if I"m already using aes? Is it probably related through the kind of the values?


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I had the very same error, even if i was making use of aes(). Therefore I used "mapping" prior to aes()

ggplot()+geom_boxplot (df, mapping = aes(x= sp, y= cov))

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Two mistakes:

Brackets need to be closed ~ ggplot and also calling histogram come afteryou specify her data collection when you speak to ggplot ~ above df. Thus there is no need to include df$sp. Sp is enough.

You are watching: Error: mapping should be created with `aes() or `aes_()`.

This code need to work (if there is nothing wrong with your data):

ggplot(df, aes(sp, cov)) + geom_histogram()

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Yes, it works . You should not use the dollar sign $ if you have specified the data already. I had actually the exact same problem and when I removed the dissension sign, it worked.

ggplot(dat1, aes(Q84, REGION, fill = Q3)) + geom_bar(stat = "Identity") + facet_grid(REGION ~ Q84)Avoid this:

ggplot(dat1, aes(dat1$Q84, dat1$REGION, to fill = Q3)) + geom_bar(stat = "Identity") + facet_grid(dat1$REGION ~ Q84)where dat1 is the name of my dataset.


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try

ggplot(df, aes(df$sp, df$cov))+ geom_histogram()instead that

ggplot(df, aes(df$sp, df$cov) + geom_histogram())displacement of base


As an additional potential solution, I found that having library(cowplot) and also library(ggplot2) loaded at the very same time made "ggsave("test.pdf", p1)" no work.

Instead, use the cowplot syntax "save_plot("test.pdf", p1)"


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