Consider the reaction: i2(g)+cl2(g)⇌2icl(g) kp= 81.9 in ~ 25 ∘c. Calculation δgrxn because that the reaction at 25 ∘c under every condition: -(part 1) at standard problems -(part 2) picl= 2.63atm ; pi2= 0.324atm ; pcl2= 0.217atm .

You are watching: Calculate δg∘rxn at 298 k for the following reaction:i2(g)+cl2(g)⇌2icl(g),kp=81.9


At standard conditions Kp= 81.9.

∵ ΔGrxn = -RTlnKp

∴ ΔGrxn = - (8.314 J/mol.K)(298.0 K)(ln(81.9)) = - 1.091 x 10⁴ J/mol.

Part 2: PICl = 2.63 atm; PI₂ = 0.324 atm; PCl₂ = 0.217 atm.

For the reaction:


I₂(g) + Cl₂(g) ⇌ 2ICl(g).

Kp = (PICl)²/(PI₂)(PCl₂) = (2.63 atm)²/(0.324 atm)(0.217 atm) = 98.38.

∵ ΔGrxn = -RTlnKp

∴ ΔGrxn = - (8.314 J/mol.K)(298.0 K)(ln(98.38)) = - 1.137 x 10⁴ J/mol.


a. ΔG°rxn in ~ standard problems : -1.09.10⁴ J/mol

b. ΔG°rxn in ~ PICl= 2.63atm ; PI2= 0.324atm ; PCl2= 0.217atm = -1.14.10⁴ J/mol

Further explanation

The equilibrium continuous is the proportion of the concentration or pressure between the result of the reaction / product and the reactant through each reaction coefficient raised

The equilibrium continuous is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

^ m ^ n} ^ ns ^ q}}}" title="55d71">

Whereas the equilibrium continuous is based upon partial pressure (Kp)

^ m ^ n} ^ ns ^ q}}}" title="1041d">

The value of Kp and also Kc have the right to be attached to the formula

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R = gas consistent = 0.0821 L.atm / mol.K

Δn = number of product coefficients-number of reactant coefficients

Gibbs (Free) power = ΔGrxn when connected to Kc / Kp:

ΔG°rxn is the traditional Gibbs free energy that reaction,

ΔGrxn = ΔG°rxn + RTlnQ

At equilibrium, Q = K and ΔGrxn = 0

ΔG°rxn = -RTlnK

a. Standard condition (T = 298 K)

ΔG°rxn = -RTlnK

ΔG°rxn = - 8,314. 298 ln 81.9 = -10914.94 J / mol = -1.09.10⁴ J/mol


b. PICl = 2.63 atm; PI2 = 0.324 atm; PCl2 = 0.217 at m.

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Kp = 98.3799

ΔG°rxn = -RTlnK

ΔG°rxn = - 8,314. 298 ln 98.3799

ΔG°rxn = -11369.1728 J/mol = -1.14.10⁴ J/mol

Learn more

calculate kc for reaction 2 in ~ the same temperature.

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the ka reaction the hcn

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Keywords : kc, kp, ΔGrxn,Gibbs (Free) Energy, conventional conditions

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What exactly id the ?grxn 

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